\[\int_{-1}^{1}\mathsf{Q}_{\nu}\left(x\right)\mathsf{Q}_{\lambda}\left(x\right)%
\,\mathrm{d}x=\frac{\left((\psi\left(\nu+1\right)-\psi\left(\lambda+1\right))(%
1+\cos\left(\nu\pi\right)\cos\left(\lambda\pi\right))+\frac{1}{2}\pi\sin\left(%
(\lambda-\nu)\pi\right)\right)}{(\lambda-\nu)(\lambda+\nu+1)},\]