\[\gamma_{\nu,m}=\dfrac{1}{2\pi}\int_{0}^{2\pi}\operatorname{me}_{\nu}'\left(t%
\right)\operatorname{me}_{-\nu-2m}\left(t\right)\,\mathrm{d}t=(-1)^{m}\dfrac{4%
\mathrm{i}}{\pi}\frac{\operatorname{me}_{\nu}'\left(0\right)\operatorname{me}_%
{-\nu-2m}\left(0\right)}{\operatorname{D}_{1}\left(\nu,\nu+2m,0\right)}.\]